Web1. Input: Price [] = {2,32,73,42,8, 5,50,87} Output: 153. Explanation: First Transaction – Trader buys shares at price 2 and sells at price 73 because, at this price, the maximum profit is 71. Second Transaction – Similarly, Trader buys again at price 5 (which is the least price next after selling at price 73 in the first transaction) and ... WebOutput: Maximum profit earned is 25 Explanation: Day 1: Sell stock y at a price of 8 Day 2: Sell stock x at a price of 3 Day 3: Sell stock x at a price of 4 Day 4: Don’t sell anything …
Best Time to Buy and Sell Stock - TutorialCup
Web7 dec. 2024 · Output: Maximum Profit: 655 : Buy at 40 : Sell at 695 Optimal solution: Buy at 100, Sell at 310 Buy at 40, Sell at 695 Total Profit = 865 Advantages of the greedy approach The worst-case time complexity of the function maximize_profit () is Θ (n). Space Complexity of the function is Θ (1). Web9 dec. 2024 · Return the maximum profit you can achieve from this transaction. If you cannot achieve any profit, return 0. Examples: Example 1: Input: prices = [7,1,5,3,6,4] Output: 5 Explanation: Buy on day 2 (price = 1) and sell … cheap cell phone battery chargers
Maximum Profit Practice GeeksforGeeks
WebYou want to maximize your profit by choosing a single day to buy one stock and choosing a different day in the future to sell that stock. Return the maximum profit you can achieve from this transaction. If you cannot achieve any profit, return 0. Input: prices = … Web2 apr. 2024 · For first day the max profit is 0 and buying price is 5. The max profit is -5. Similarly its again -5 and 3 for second and third days. And the max profit from the first transaction till fourth day is 3. Add the current day price to max profit. And we get the max profit of 53. We will get the maximum of 6 and 53. Its 53. Web29 nov. 2016 · Find maximum profit earned by buying and selling shares any number of times Given a list containing future prediction of share prices, find the maximum profit … cheap cell phone batteries free shipping